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Suppose events A and B are independent with P(A) = 0.6 and P(A or B) = 0.8726.

Find P(B). Question 14 1 pts Suppose events A and B are events with P(A) = 0.08, P(B) = 0.4, and P(A or B) = 0.24. Find P(A and B). 0.032

User Khilen
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Final answer:

To find the probability of event B, subtract the probability of event A from the probability of event A or B. Therefore, the probability of event B is 0.2726.

Step-by-step explanation:

To find the probability of event B, subtract the probability of event A from the probability of event A or B. Therefore, the probability of event B is 0.2726. To find the probability of event B, we can use the formula P(B) = P(A or B) - P(A). In this case, we are given that P(A) = 0.6 and P(A or B) = 0.8726. Substituting these values into the formula, we have P(B) = 0.8726 - 0.6 = 0.2726. Therefore, the probability of event B is 0.2726.

User Ben Jaspers
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