Question

Diana is packing a lunch that will include an orange. Diana has 3 navel oranges, 5 mandarin oranges, and 4 Valencia oranges. If Diana selects an orange at random, what is the probability that she selects a navel orange?

Give your answer as a simplified fraction.

Answer 1

1/4

Explanation:

Number of navel oranges = 3.

Number of mandarin oranges = 5.

Number of Valencia oranges = 4.

Let N be an event that Diana selects navel orange.

The total number of oranges Diana has:

n(T)=3+5+4=12n(T)=3+5+4=12

Number of navel Oranges is:

n(N)=3n(N)=3

The probability that Diana selects a navel orange is:

P(N)=n(N)n(T)=312=14P(N)=n(N)n(T)=312=14

Hence, the probability that Diana selects a navel orange is 1414.

Answer 2

Explanation:

1. Ok. Probability is something out of all. Add to get the bottom base of the probability.

3+4+5= 12

2. Probability is something out of something so 3 navel oranges can be represented out of 12 oranges.

3 out of 12

3. Make as fraction:

3 out of 12=

3/12=

1/4 or 25 Percent!

Answer: 1/4 or 25% ( If wanted as Percent)