Question

The circle with cetter (3,-5) and diameter 22

Answer 1

The equation of the circle with a center at (3,-5) and a diameter of 22 is x^2 + y^2 - 6x + 10y - 87 = 0.

Step-by-step explanation:

The circle with a center at (3,-5) and a diameter of 22 can be represented by the equation of a circle.

Using the formula (x - h)2 + (y - k)2 = r2, where (h,k) is the center of the circle and r is the radius, we can substitute the given values:

(x - 3)2 + (y + 5)2 = 112

Expanding and simplifying the equation gives:

x2 - 6x + 9 + y2 + 10y + 25 = 121

x2 + y2 - 6x + 10y - 87 = 0

So, the equation of the circle is x2 + y2 - 6x + 10y - 87 = 0.

corrected question: Find the equation of the circle with cetter (3,-5) and diameter 22