Final answer:
The expression 10[21+3(6-2)^(2)]+4-:2 is solved by applying the order of operations, which results in final answer of 347.
Step-by-step explanation:
The student's question involves applying the order of operations to evaluate an arithmetic expression. To solve the expression 10[21+3(6-2)^(2)]+4-:2, we follow these steps:
- Inside the brackets, calculate the exponent first: (6-2)^(2) = 4^(2) = 16.
- Multiply the result of the exponent by 3: 3 × 16 = 48.
- Add this result to 21: 21 + 48 = 69.
- Multiply the entire bracket by 10: 10 × 69 = 690.
- Add the number 4: 690 + 4 = 694.
- Since '-:2' likely means '÷ 2', divide by 2: 694 ÷ 2 = 347.
The final result of the order of operations on the given expression is 347.