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Use the rules for order of operations to 10[21+3(6-2)^(2)]+4-:2

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Final answer:

The expression 10[21+3(6-2)^(2)]+4-:2 is solved by applying the order of operations, which results in final answer of 347.

Step-by-step explanation:

The student's question involves applying the order of operations to evaluate an arithmetic expression. To solve the expression 10[21+3(6-2)^(2)]+4-:2, we follow these steps:

  1. Inside the brackets, calculate the exponent first: (6-2)^(2) = 4^(2) = 16.
  2. Multiply the result of the exponent by 3: 3 × 16 = 48.
  3. Add this result to 21: 21 + 48 = 69.
  4. Multiply the entire bracket by 10: 10 × 69 = 690.
  5. Add the number 4: 690 + 4 = 694.
  6. Since '-:2' likely means '÷ 2', divide by 2: 694 ÷ 2 = 347.

The final result of the order of operations on the given expression is 347.

User VladOhotnikov
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