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0.12x=0.09y+492.99 put the system of linear equations .

User Adi Levin
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1 Answer

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Final answer:

To solve the system of linear equations 0.12x = 0.09y + 492.99, we need to rearrange the equation in the form y = mx + b. The resulting system of linear equations is 0.12x = 0.09y + 492.99 and y = 1.33x - 5477.67.

Step-by-step explanation:

To solve the system of linear equations 0.12x = 0.09y + 492.99, we can start by rearranging the equation to the form y = mx + b, where m is the slope and b is the y-intercept. This can be achieved by isolating y on one side of the equation:

0.12x - 0.09y = 492.99

Now, we can rewrite the equation as:

-0.09y = -0.12x + 492.99

Multiplying both sides by -1 to make the coefficient of y positive:

0.09y = 0.12x - 492.99

Divide both sides by 0.09:

y = (0.12/0.09)x - (492.99/0.09)

Simplifying:

y = 1.33x - 5477.67

Therefore, the system of linear equations is:

0.12x = 0.09y + 492.99

y = 1.33x - 5477.67

User Touhami
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