Final answer:
The last factor needed for the prime factorization of 220 is 2.
Step-by-step explanation:
The last factor that Sutton needs for the prime factorization of 220 is 2. Prime factorization is the process of breaking down a number into its prime factors. To find prime factors, we divide the number by prime numbers until we can no longer divide evenly. In this case, we start by dividing 220 by 2, which gives us 110. We continue dividing by 2 until we can no longer divide evenly, which leaves us with a quotient of 55. 55 cannot be divided evenly by 2, so we move on to the next prime number, which is 3. However, 3 does not divide evenly into 55, so we move on to the next prime number, which is 5. 5 divides evenly into 55, leaving us with a quotient of 11.
Finally, 11 is a prime number and cannot be divided further, so we have successfully found the prime factors of 220 as 2 * 2 * 5 * 11.