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The length and width of a rectangle whose length is 14 centimeters more than its widt. The width of the rectangle is

User Vishakh
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Final answer:

To find the dimensions of the rectangle, set up the equation using the perimeter formula and solve for width. The length is then found by adding 14 to the width, yielding a width of 59 meters and a length of 73 meters.

Step-by-step explanation:

The student is tasked with finding the dimensions of a rectangle where the length is 14 meters more than the width and the perimeter is 264 meters. To solve for the dimensions of the rectangle, you can use the perimeter formula for rectangles, P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.

Let's define the width of the rectangle as w meters. According to the problem, the length is w + 14 meters. So we can express the perimeter as:

  • 264 = 2(w + 14) + 2w

To find the width, combine like terms and solve for w:

  • 264 = 2w + 28 + 2w
  • 264 = 4w + 28
  • 236 = 4w
  • w = 59

Now that we know the width is 59 meters, we can find the length:

  • Length = width + 14 = 59 + 14 = 73 meters

The dimensions of the rectangle are 59 meters in width and 73 meters in length.

User Nikhil G
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