Question

For problems 1-6, determine the Axis of Symmet for each quadratic in standard or vertex form. Rece the answer column. f(x)=2x^(2)+16x+38

Answer 1

The axis of symmetry for the given quadratic function f(x) = 2x^2 + 16x + 38 is x = -4.

Step-by-step explanation:

To determine the axis of symmetry of a quadratic function in standard form, we can use the formula x = -b/(2a). In the given quadratic function f(x) = 2x^2 + 16x + 38, the coefficient of x^2 is a = 2 and the coefficient of x is b = 16. Plugging these values into the formula, we get x = -16/(2*2) = -4.

Therefore, the axis of symmetry for the given quadratic function is x = -4.