Question

the equation h=-16t²+48t+4 (where t)= time in seconds and h=( height in feet ) What will be the height of the ball after 2 seconds?

Answer 1

To find the height of the ball after 2 seconds, substitute t = 2 into the given equation h = -16t² + 48t + 4. Therefore, the height of the ball after 2 seconds is 36 feet.

Step-by-step explanation:

To find the height of the ball after 2 seconds, substitute t = 2 into the given equation h = -16t² + 48t + 4.

h = -16(2)² + 48(2) + 4

Calculate each term:

h = -16(4) + 96 + 4

h = -64 + 96 + 4

h = 36

Therefore, the height of the ball after 2 seconds is 36 feet. This result is obtained by plugging the time (t = 2) into the equation, which models the height of the ball as a function of time under the influence of gravity (represented by the quadratic term -16t² and initial conditions (the constants 48 and 4).