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The scores of four students in a mathematics test are 79,83 , 92 and 80. Aureila's score is 6 more than the average score of the four students and her score. What is Aureila's score in the mathematics test?

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Final answer:

Aurelia's score on the mathematics test is calculated by initially finding the average of the four provided scores and then setting up an equation based on the information that her score is 6 more than the average of all five scores. Solving the equation yields a score of 91 for Aurelia.

Step-by-step explanation:

The question asks us to find Aurelia's score in a mathematics test given that her score is 6 more than the average score of the four students and her score. First, we need to calculate the average of the four scores provided: 79, 83, 92, and 80.

We begin by summing these scores:
79 + 83 + 92 + 80 = 334

Next, we calculate the average by dividing the sum by the number of scores:
Average = 334 / 4 = 83.5

Since Aurelia's score is 6 more than the average of the five scores (the four given plus Aurelia's), we can set up the equation:
Aurelia's score = Average of five scores + 6

Let A represent Aurelia's score. The average of the five scores will be (334 + A) / 5, so the equation becomes:
A = (334 + A) / 5 + 6

Multiplying both sides by 5 to get rid of the fraction gives us:
5A = 334 + A + 30

Combining like terms and solving for A gives us:
4A = 364

A = 91

Therefore, Aurelia's score on the mathematics test is 91.

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