Question

Jerry is 7 years older than Jennifer. In three years, Jerry will be twice as old as Jennifer. Let Jerry be X Let Jennifer be Y. What is their present ages.

Answer 1

Using a system of equations, we found that Jerry is currently 11 years old, and Jennifer is 4 years old, based on the given information that Jerry is 7 years older than Jennifer and will be twice her age in three years.

Step-by-step explanation:

The student's question involves determining the present ages of Jerry and Jennifer using a system of equations. We let Jerry's age be X and Jennifer's age be Y. The first equation is X = Y + 7, because Jerry is 7 years older than Jennifer. The second equation is X + 3 = 2(Y + 3), which represents that in three years, Jerry will be twice as old as Jennifer.

So, let's solve this system of equations step-by-step:

1. Write down the given equations:
   
   X = Y + 7 (1)
   
   X + 3 = 2(Y + 3) (2)
2. Substitute the value of X from equation (1) into equation (2):
   
   Y + 7 + 3 = 2(Y + 3)
3. Simplify and solve for Y:
   
   Y + 10 = 2Y + 6
   
   10 - 6 = Y
   
   Y = 4
4. Now that we have Y, plug it back into equation (1) to find X:
   
   X = 4 + 7
   
   X = 11

Therefore, Jerry is 11 years old and Jennifer is 4 years old currently.