Final answer:
To find all the numbers such that when three is added to their square, the result is twenty-eight, we can set up an equation: x^2 + 3 = 28. Solving for x, we find that x can be either 5 or -5.
Step-by-step explanation:
To find all the numbers such that when three is added to their square, the result is twenty-eight, we can set up an equation.
Let the number be represented by x. Then, the equation becomes: x^2 + 3 = 28
Solving for x, we subtract 3 from both sides of the equation: x^2 = 25
Next, we take the square root of both sides to find the value of x. Since a number squared can have two solutions (a positive and a negative), we take the positive and negative square root of 25. Therefore, x can be either 5 or -5.