Final answer:
The box will take approximately 2.84 seconds to hit the ground when falling from a height of 145 feet.
Step-by-step explanation:
To find the time it takes for the box to hit the ground, we can use the equation s = ut + 1/2at^2, where s is the distance, u is the initial velocity, a is the acceleration due to gravity, and t is the time. In this case, the box is falling vertically downwards, so the initial velocity is 0 m/s and the acceleration due to gravity is -9.8 m/s^2. The distance traveled is 145 feet, which is approximately 44.2 meters.
Setting s = 44.2 m, u = 0 m/s, and a = -9.8 m/s^2, we can solve for t:
44.2 = 0 × t + 1/2 × (-9.8) × t^2
44.2 = -4.9t^2
t^2 = 9.02
t = √(9.02) ≈ 2.84 seconds