Question

A plumber repaired 12 leaky faucets last week. The plumber estimated that each leaky faucet wasted 5.7 gallons of water per day. The town charges $2.06 for every 1,000 gallons of water used. Which is the closest estimate of the combined annual savings from repairing the 12 leaky faucets?

Answer 1

To find the combined annual savings from repairing the 12 leaky faucets, calculate the total amount of water wasted in a year and multiply it by the cost of water per gallon.

Step-by-step explanation:

To find the combined annual savings from repairing the 12 leaky faucets, we need to calculate the total amount of water wasted by the faucets in a year and then multiply it by the cost of water per gallon.

The amount of water wasted per day by one faucet is 5.7 gallons. So, in a year, each faucet would waste 5.7 x 365 = 2080.5 gallons.

The total amount of water wasted by the 12 faucets in a year would be 2080.5 x 12 = 24966 gallons.

The town charges $2.06 for every 1000 gallons of water used, so the cost of 24966 gallons of water would be 24966 / 1000 x $2.06 = $51.39.

Therefore, the closest estimate of the combined annual savings from repairing the 12 leaky faucets would be $51.39.