Final answer:
The area of the larger square, with a side length of 8 inches, is 4 times larger than the area of the smaller square, which has a side length of 4 inches.
Step-by-step explanation:
To compare the area of two squares where one has dimensions that are twice the size of the other, you first need to find the dimensions of the larger square. Given that Marta's first square has a side length of 4 inches, the larger square, being twice as large, will have a side length of 8 inches.
Next, you calculate the area of both squares. The area of the smaller square is 4 inches × 4 inches = 16 square inches, and the area of the larger square is 8 inches × 8 inches = 64 square inches.
Finally, to find out how much larger the area of the larger square is compared to the smaller square, you write a ratio. The ratio of the areas is 64 square inches:16 square inches, which simplifies to 4:1. Therefore, the area of the larger square is 4 times larger than the area of the smaller square.