Question

jared wanted to fins three consecutive even intergers whose sum was 4 times the first of those integers. he let k represent the first integer, then wrote and solved this equation: k+(k+1)+(k+2)=4k.

Answer 1

In this Mathematics question, we need to find three consecutive even integers whose sum is 4 times the first integer.

Step-by-step explanation:

The subject of this question is Mathematics, and it is a High School level question.

In this problem, Jared is looking for three consecutive even integers whose sum is 4 times the first integer. Let's represent the first integer as 'k'. The sum of these three consecutive even integers can be represented as k + (k+2) + (k+4). According to the problem, this sum is equal to 4k.

So, we can write the equation as k + (k+2) + (k+4) = 4k. We can solve this equation to find the value of 'k' and then find the three consecutive even integers.