Question

in a game, the probability of spinnimg a 5 or 6 is (2)/(3). how many times would you expect to land on a number other than 5 or 6 if you spin the spinner 15 times?

Answer 1

With a probability of 2/3 for spinning a 5 or 6, the expected number of times to land on another number in 15 spins is 5, as the probability of not spinning a 5 or 6 is 1/3.

Step-by-step explanation:

The question is about finding the expected number of times a spinner lands on a number other than 5 or 6 given the probability of spinning a 5 or 6 is (2)/(3). If the probability of spinning a 5 or 6 is 2/3, then the probability of landing on a number other than 5 or 6 is 1 - (2/3) = 1/3. When spinning the spinner 15 times, you can calculate the expected number of times for an event by multiplying the probability of the event by the number of trials, which in this case, gives us 1/3 * 15 = 5. Therefore, we would expect to land on a number other than 5 or 6 exactly 5 times out of 15 spins. This is an example of using expected values in probability.