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Find the 62ⁿᵈ term of the following 15,22,29,36,dots

User XPav
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Final answer:

To determine the 62nd term of an arithmetic sequence with a common difference of 7, we apply the formula for the nth term to get an answer of 442.

Step-by-step explanation:

To find the 62nd term of the sequence (15, 22, 29, 36, ...), we need to recognize what type of sequence it is. This sequence represents an arithmetic sequence because each term increases by a constant difference, which is 7 (22 - 15 = 29 - 22 = 36 - 29 = 7).

The general formula for the nth term of an arithmetic sequence is an = a1 + (n - 1)d, where a1 is the first term, d is the common difference, and n is the term number.

Using the given sequence:
a1 = 15
d = 7
n = 62

We can now find the 62nd term:
a62 = 15 + (62 - 1) × 7
a62 = 15 + 61 × 7
a62 = 15 + 427
a62 = 442

Therefore, the 62nd term of the sequence is 442.

User Foebu
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