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Factor the sum or difference of two cubes. t^(3)+729

User Sherri
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1 Answer

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Final answer:

To factor the sum of two cubes, we can use the formula (a³ + b³) = (a + b)(a² - ab + b²). In this case, t³ + 729 = (t + 9)(t² - 9t + 81).

Step-by-step explanation:

To factor the sum of two cubes, such as

t³ + 729

we can use the formula:

a³ + b³ = (a + b)(a² - ab + b²)

In this case, we have

t³ + 729 = (t + 9)(t² - 9t + 81)

Therefore, the factored form of

t³ + 729

is

(t + 9)(t² - 9t + 81)

User Biela Diela
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