Final answer:
To solve the problem, the smallest consecutive integer is defined as n, leading to the integers 25, 26, and 27, with the sum of the first two exceeding the third by 24.
Step-by-step explanation:
The question asks to find 3 consecutive integers where the sum of the first two is 24 more than the third.
Let's define the smallest of these integers as n. Therefore, the next two consecutive integers would be n+1 and n+2. According to the condition given, n + (n + 1) = (n + 2) + 24.
Simplifying this equation we have 2n + 1 = n + 26, which leads to n = 25. So, the three consecutive integers are 25, 26, and 27.