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Find the line's slope and a point on the li y+5=-(1)/(3)(x-4)

User Makis
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Final answer:

The slope of the line y+5=-(1/3)(x-4) is -1/3, and a point on the line is (0, -13/3).

Step-by-step explanation:

To find the slope and a point on the line y+5=-(1/3)(x-4), we can rewrite the equation in slope-intercept form, which is y = mx + b. In this case, m represents the slope and b represents the y-intercept.

Starting with the given equation, y + 5 = -(1/3)(x - 4), we subtract 5 from both sides to isolate y: y = -(1/3)(x - 4) - 5.

Now, we can see that the slope of the line is -1/3. A point on the line can be found by substituting any x value into the equation and solving for y. For example, if we let x = 0, y = -(1/3)(0 - 4) - 5 = -13/3.

User Matt Dillard
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