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What is the number of real solutions? x² =-7x+7

User Ramarren
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Final answer:

The equation x² = -7x + 7 can be rearranged to the standard quadratic form x² + 7x - 7 = 0. Checking the discriminant, which is 77 and positive, reveals that there are two real solutions to this quadratic equation.

Step-by-step explanation:

To determine the number of real solutions for the equation x² = -7x + 7, we need to rearrange it into the standard quadratic form. By moving all the terms to one side, we get:

x² + 7x - 7 = 0

This equation is of the form ax² + bx + c = 0, where a = 1, b = 7, and c = -7. To find the solutions, we use the quadratic formula:

x = √[-b ± √(b² - 4ac)] / (2a).

Since we are looking for real solutions, we must check the discriminant (b² - 4ac). If the discriminant is positive, there are two real solutions; if it is zero, there is one real solution; and if it's negative, there are no real solutions.

For our equation:

Discriminant = b² - 4ac = (7)² - 4(1)(-7) = 49 + 28 = 77.

Since 77 is positive, there are two real solutions to the equation.

User Eliasdx
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