Question

The capacitance of the given capacitor is μF (Use scientific notation. Use the multiplication symbol in the math palette as needed Round to two decimal places as needed.)

(5.71×10⁻⁸)×( 9/ 3.00×10⁻³)

Answer 1

To find the total capacitance of two capacitors connected in series, use the formula 1/C = 1/C1 + 1/C2. Plug in the given values and simplify to find the total capacitance.

Step-by-step explanation:

To find the total capacitance of two capacitors connected in series, we use the formula:

1/C = 1/C1 + 1/C2

In this case, the capacitance of the first capacitor is 5.71x10^-8 μF and the capacitance of the second capacitor is (9/3.00x10^-3) μF. Plugging these values into the formula:

1/C = 1/(5.71x10^-8) + 1/((9/3.00x10^-3))

Simplifying, we get:

1/C = 1/(5.71x10^-8) + 3/(9x10^-3) = 1.23 x 10^7 F

Therefore, the total capacitance of the two capacitors connected in series is 1.23 x 10^7 F.