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Suppose the area of a square is x²-10x+25. What is the perimeter of the sqaure?

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Final answer:

The perimeter of the square, where the area is given as x²-10x+25, is 4x-20 after factoring the area expression and multiplying the side length by 4.

Step-by-step explanation:

The area of the square is given as x²-10x+25. To find the side length of the square, we need to take the square root of the area. The expression for the area is a perfect square trinomial and can be factored as (x-5)². Therefore, the side length of the square is x-5. Since the perimeter of a square is 4 times the side length, the perimeter P of the square is 4(x-5), which simplifies to 4x-20.

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