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The sum of two numbers is 41 . The larger number is 23 more than the smaller number. What are the numbers?

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Final answer:

The two numbers are 9 and 32, with 9 being the smaller number and 32 being the larger number. The larger number is 23 more than the smaller number, and together they sum up to 41.

Step-by-step explanation:

The student has asked to find two numbers whose sum is 41, with the larger number being 23 more than the smaller number.

Let's denote the smaller number as x and the larger number as y. According to the problem, we have two equations:

  1. x + y = 41
  2. y = x + 23

We can substitute the second equation into the first to find the value of x:

x + (x + 23) = 41

2x + 23 = 41

2x = 41 - 23

2x = 18

x = 18 / 2

x = 9

Now that we know x, we can find y by substituting x back into the second equation:

y = 9 + 23

y = 32

Therefore, the two numbers are 9 and 32, with 9 being the smaller number and 32 being the larger number.

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