Final answer:
The two numbers are 9 and 32, with 9 being the smaller number and 32 being the larger number. The larger number is 23 more than the smaller number, and together they sum up to 41.
Step-by-step explanation:
The student has asked to find two numbers whose sum is 41, with the larger number being 23 more than the smaller number.
Let's denote the smaller number as x and the larger number as y. According to the problem, we have two equations:
- x + y = 41
- y = x + 23
We can substitute the second equation into the first to find the value of x:
x + (x + 23) = 41
2x + 23 = 41
2x = 41 - 23
2x = 18
x = 18 / 2
x = 9
Now that we know x, we can find y by substituting x back into the second equation:
y = 9 + 23
y = 32
Therefore, the two numbers are 9 and 32, with 9 being the smaller number and 32 being the larger number.