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Find a subunit fraction that has consecutive numerator and denominator natural numbers, and their sum is 51.

User Misam
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Final answer:

There is no subunit fraction with consecutive numerator and denominator natural numbers whose sum is 51.

Step-by-step explanation:

To find a subunit fraction that has consecutive numerator and denominator natural numbers, and their sum is 51, we can set up the equation:

x/(x+1) = 51

Where x is the numerator and x+1 is the denominator. We can solve this equation by cross multiplying and then solving for x:

x = 51(x+1)

Simplifying further, we get:

x = 51x + 51

Subtracting 51x from both sides, we get:

x - 51x = 51

-50x = 51

Dividing both sides by -50, we get:

x = -51/50

Since we are looking for consecutive natural numbers, x must be a positive integer. Therefore, there is no subunit fraction with consecutive numerator and denominator natural numbers whose sum is 51.

User Jude
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