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Given the variance 11.35 what is the value of standard Deviation? (you answer must be 2 decimal place only )3

User Binzhang
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Final answer:

The standard deviation of a dataset with a variance of 11.35 is approximately 3.37 when rounded to two decimal places.

Step-by-step explanation:

The value of the standard deviation is the square root of the variance. Given the variance of 11.35, we can find the standard deviation by taking the square root:

Standard Deviation = √Variance

Standard Deviation = √11.35

Standard Deviation ≈ 3.37 (rounded to two decimal places)

Given the variance of 11.35, the value of the standard deviation can be found by taking the square root of the variance. The standard deviation (S) is equal to the square root of the variance. Therefore:

S = √11.35

To two decimal places, the standard deviation is:

S ≈ 3.37

This calculation is critical for understanding the spread of a data set around the mean and is widely used in statistical analysis.

User Aleth
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