128k views
3 votes
Find the values of a, b such that the function f(x) =sin(ax²) / (3x) for x > 0, (1-x)² + b for x ≤ 0 ,

User Clash
by
7.3k points

1 Answer

4 votes

Final answer:

To find the values of a and b for the given function, we need to consider two different cases for x: x > 0 and x ≤ 0. For x > 0, the function is f(x) = sin(ax²) / (3x), and for x ≤ 0, the function is f(x) = (1-x)² + b. In both cases, a and b can be any real numbers.

Step-by-step explanation:

To find the values of a and b for the given function, we need to consider the two different cases for x: x > 0 and x ≤ 0. For x > 0, the function is f(x) = sin(ax²) / (3x). For x ≤ 0, the function is f(x) = (1-x)² + b. Let's solve for each case separately.

Case 1: x > 0
Since x > 0, we can simplify the function to f(x) = sin(ax²) / (3x).
This function does not have any specific values for a and b as they can be any real numbers.

Case 2: x ≤ 0
Since x ≤ 0, we can simplify the function to f(x) = (1-x)² + b.
Again, this function does not have any specific values for a and b as they can be any real numbers.

User Jeff Bennett
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.