Final answer:
To find the general indefinite integral of ∫ (9/s - 2/s²) ds, split it into two separate integrals: ∫(9/s)ds and ∫(-2/s²)ds. Solve the first integral as ln|s| and the second integral as 2/s. The general indefinite integral is ln|s| - 2/s + C.
Step-by-step explanation:
To find the general indefinite integral of ∫ (9/s - 2/s²) ds, we can split it into two separate integrals: ∫(9/s)ds and ∫(-2/s²)ds. The first integral can be solved as the natural logarithm of the absolute value of s: ln|s|. The second integral can be solved as 2/s. Therefore, the general indefinite integral is ln|s| - 2/s + C, where C is the constant of integration.