Final Answer:
![\(A = 1\) and \(B = e^{(1)/(6)}\). On the interval \((A, B]\), \(f(x)\) is increasing.](https://img.qammunity.org/2024/formulas/mathematics/high-school/zizq9ns0hk6tk1giewmcdfl1cyx7cx4njl.png)
Step-by-step explanation:
The critical points of the function
occur where the numerator or denominator equals zero or is undefined. In this case, the function is undefined at
due to the natural logarithm, and the denominator becomes zero at
is a critical point.
To find B, set the denominator equal to zero and solve for x:
![\[x^6 = e^{(1)/(6)} \implies x = e^{(1)/(6)}.\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/fxt6002oe64ubt9r06kh4a8ivn6nssgkbh.png)
So,
on the interval
using the quotient rule:
![\[f'(x) = (1 - 6\ln x)/(x^7).\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/miivp5a8bsip1ce2dzmgu8l6n2mqoh5ex3.png)
On the interval
Thus,
![\(f(x)\) is increasing on \((A, B]\).](https://img.qammunity.org/2024/formulas/mathematics/high-school/wvnwggyafp0068yy80jgixn5q1s1bxoktn.png)