Final answer:
To conclude the velocity of the ball at t = 2, one should consider both horizontal velocity, which remains constant, and vertical velocity, which changes due to gravity at a rate of 9.8 m/s².
Step-by-step explanation:
The conclusion for the velocity of the ball at t = 2 can be determined by examining the information given and applying the appropriate physics equations. To find the instantaneous velocity at t = 2 s, we would typically use the derivative of the position function at that time. However, based on the provided information, it looks like the graph shows a horizontal velocity as a constant value until t = 0.7 s, which implies that at t = 2 s, the horizontal velocity would still be that constant positive value. If the object is in projectile motion, the vertical velocity at t = 2 s would be affected by gravity, and we can use kinematic equations to calculate this using the initial vertical velocity and the acceleration due to gravity.
Assuming no other forces are acting on the ball, and the horizontal velocity remains constant because there is no horizontal acceleration (as indicated by the graph), the horizontal velocity at t = 2 s would simply be the initial velocity. For the vertical velocity, the provided graph suggests the vertical component starts at 4.9 m/s and decreases with a slope of -9.8 m/s². Therefore, the velocity at t = 2 s can be found by subtracting the product of the acceleration (9.8 m/s²) and the time (2 s) from the initial velocity.