Question

Teagan and Jay dyn painted their rooms using paint in cans of the same size. Teagan used 1(1/2) cans of paint. Jay dyn used 2(3/4) cans of paint. How many times as much paint did Jay dyn use as _______

Answer 1

Jay dyn used 11/6 times as much paint as Teagan. For the painting job time, the linear equation is T = 4 + 1A, where T is the total time and A is the area in thousands of square feet.

Step-by-step explanation:

To determine how many times as much paint Jay dyn used compared to Teagan, we can simply divide the quantity of paint Jay dyn used by the quantity Teagan used. Teagan used 1(1/2) or 3/2 cans of paint, and Jay dyn used 2(3/4) or 11/4 cans of paint.

Now, let's calculate:

2(3/4) ÷ 1(1/2) = (11/4) ÷ (3/2) = (11/4) × (2/3) = 22/12 = 11/6

Jay dyn used 11/6 times as much paint as Teagan.

When expressing a linear equation for the setup time and painting time, we can use the formula:

Total Time (hours) = Setup Time (hours) + (Painting Time per 1000 sq ft) x (Area in 1000 sq ft)

Translated into an equation, this becomes:

T = 4 + 1A

Where T is the total time and A is the area in thousands of square feet.