Final answer:
There are approximately 9.9433 x 10^23 atoms in 1.65 mol of pure aluminum.
Step-by-step explanation:
To determine the number of atoms in 1.65 mol of pure aluminum, we can use Avogadro's number, which is approximately 6.022 x 10^23. One mole of any substance contains this many particles (atoms, molecules, etc.). Therefore, we can calculate the number of atoms as follows:
Number of atoms = (1.65 mol) x (6.022 x 10^23 atoms/mol)
Number of atoms = 9.9433 x 10^23 atoms
So, there are approximately 9.9433 x 10^23 atoms in 1.65 mol of pure aluminum.