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The Square circle: x²+y²+12x+2y+12=0 f the circle.

1 Answer

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Final answer:

The given equation represents a circle with center (-6, -1) and radius √37.

Step-by-step explanation:

The given equation is a quadratic equation in two variables, x and y. It represents a circle when the coefficients of x² and y² are both equal and their sum is non-zero. In this case, the coefficients of x² and y² are both 1, and their sum is 2. Therefore, the equation represents a circle. To find the center and radius of the circle, we need to complete the square for both x and y.

Completing the square for x, we have (x+6)² - 36. Completing the square for y, we have (y+1)² - 1. So, the center of the circle is (-6, -1) and the radius is √(36+1) = √37. Therefore, the equation represents a circle with center (-6, -1) and radius √37.

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