Final answer:
The polynomial 9 - x² + (1/6)x when rearranged in standard form becomes -x² + (1/6)x + 9, which is written with the terms in descending order of their exponents.
Step-by-step explanation:
To rewrite the polynomial 9 - x² + (1/6)x in standard form, we need to arrange the terms in descending order of their exponents. The standard form of a polynomial is typically written as ax² + bx + c, where 'a', 'b', and 'c' are constants, and 'x' represents the variable. In this case, the polynomial is already close to standard form, but we need to rearrange the terms.
The given polynomial after rearranging is: -x² + (1/6)x + 9.
To further clarify, the term -x² represents the quadratic term, (1/6)x is the linear term, and 9 is the constant term.