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Let f(2)=4,f ′ (2)=4, then lim x→2 then xf(2)−2f(x)/x−2 is

User Remudada
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1 Answer

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Final answer:

The limit of the given expression is -6.

Step-by-step explanation:

To find the limit of the given expression, we can use L'Hôpital's Rule. Let's differentiate the numerator and denominator separately:

f(2) = 4

f'(2) = 4

lim(x→2) [xf(2)−2f(x)/(x−2)] = lim(x→2) [f(2) + x*f'(2) - 2f(x)]/(x-2)

Substituting the given values, we have:

lim(x→2) [4 + 2x - 2f(x)]/(x-2)

Now, let's apply L'Hôpital's Rule by differentiating the numerator and denominator again:

lim(x→2) [2 - 2f'(x)] = 2 - 2f'(2) = 2 - 2(4) = -6

User UNagaswamy
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