Final answer:
To compute the derivative of y = √sin(cos²x), apply the chain rule and differentiate the outer function, the inner function, and the exponent function. The derivative is dy/dx = (1/2√sin(cos²x)) * (cos(sin(cos²x))) * (-sin(2cos²x)).
Step-by-step explanation:
To compute the derivative of the given function, y = √sin(cos²x), we can use the chain rule. Let's break it down step by step:
- Start by differentiating the outer function, which is √u. The derivative of √u is (1/2√u) times the derivative of u.
- Next, differentiate the inner function, u = sin(cos²x). The derivative of sin(u) is cos(u) times the derivative of u.
- Finally, find the derivative of the exponent function, u = cos²x. The derivative of cos²u is -sin(2u) times the derivative of u.
Combining these steps, we get the derivative of y as: dy/dx = ((1/2√sin(cos²x)) * (cos(sin(cos²x))) * (-sin(2cos²x)))