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Karen, Reuben, and Chang have a total of $107 in their wallets. Chang has 3 times what Reuben has. Karen has $8 less than Reuben. How much does each have?

User Pyro
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1 Answer

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Final answer:

By setting up a system of linear equations and solving for the variables, we find that Reuben has $23, Chang has $69, and Karen has $15.

Step-by-step explanation:

The question involves solving a system of linear equations to determine how much money Karen, Reuben, and Chang each have. Let's define the following variables: let R be the amount of money Reuben has, C be the amount Chang has, and K be the amount Karen has. According to the problem, Chang has 3 times what Reuben has (C = 3R), Karen has $8 less than Reuben (K = R - 8), and together they have $107 (R + C + K = 107).

To find out how much each person has, we set up the equations:

Substituting the expressions for C and K from equations 1 and 2 into equation 3, we get:

R + 3R + (R - 8) = 107

Combining like terms, we get:

5R - 8 = 107

Adding 8 to both sides, we get:

5R = 115

Dividing both sides by 5, we get:

R = 23

We can now determine the amounts for Chang and Karen:

C = 3R = 3(23) = $69

K = R - 8 = 23 - 8 = $15

Therefore, Reuben has $23, Chang has $69, and Karen has $15.

User Karudi
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