Final answer:
The number of distinct ways to award the 1st, 2nd, and 3rd prizes among the winners is 3.
Step-by-step explanation:
The problem states that there are 100 raffle tickets sold and 3 of them are winners. We need to find the number of distinct ways to award the 1st, 2nd, and 3rd prizes among the winners.
Since we need to find the number of distinct ways, we use the concept of permutations. The formula for permutations is P(n, r) = n! / (n-r)!, where n is the total number of items and r is the number of items taken at a time.
In this case, the total number of items is 3 (winners) and we need to take all 3 at a time. So, the number of distinct ways to award the prizes is P(3, 3) = 3! / (3-3)! = 3! / 0! = 3.