Question

Homer sells tickets for admission to your school play and collects a total of $104. Admission prices are $6 for adults and $4 for children. 21 tickets were sold in total. How many children's tickets were sold?

Answer 1

To solve this problem, we can use a system of equations to represent the number of adult and children's tickets sold. By solving the system of equations, we find that 11 children's tickets were sold.

Step-by-step explanation:

To solve this problem, we can use a system of equations. Let x represent the number of adult tickets sold, and let y represent the number of children's tickets sold. We have the following equations:

1. 1. x + y = 21 (total number of tickets sold)
   2. 6x + 4y = 104 (total amount collected)

We can solve the system of equations using substitution or elimination. Let's solve it using elimination:

1. 1. Multiply the first equation by 4: 4x + 4y = 84
   2. Subtract the second equation from the first: (4x + 4y) - (6x + 4y) = 84 - 104
   3. -2x = -20
   4. Divide both sides by -2: x = 10

Substitute the value of x into the first equation to find the value of y:

1. 1. 10 + y = 21
   2. y = 21 - 10
   3. y = 11

Therefore, 11 children's tickets were sold.