Question

An adult movie ticket cost $7. A child movie ticket cost $5.A tourist paid $228 in all for 40 movie tickets. How many adult movie tickets were there if he had paid $32 more for the adult movie tickets

Answer 1

To find the number of adult movie tickets purchased, a system of equations was created, taking into account the total cost, the number of tickets, and the difference in cost between adult and child tickets. Solving the system, we find that 28 adult tickets and 12 child tickets were purchased.

Step-by-step explanation:

The student is asking how many adult movie tickets were purchased if a tourist paid $228 in total for 40 movie tickets, with adult tickets costing $7 each and child tickets costing $5 each, and $32 more was paid for adult tickets than for child tickets. We can use a system of two equations to solve this problem:

• Let A be the number of adult tickets.
• Let C be the number of child tickets.

We have two equations:

1. 7A + 5C = 228 (The total cost of the tickets is $228.)
2. A + C = 40 (There are a total of 40 tickets.)
3. 7A - 5A = 32 (The difference in cost between adult and child tickets is $32.)

From these equations, we get:

After solving, we find that A = 28 and C = 12. So, the tourist bought 28 adult tickets and 12 child tickets.