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-5x²-12x+5-23+3x²=0 er your answer rounded to the nearest hundredth.

User Suraken
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1 Answer

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Final answer:

To solve the quadratic equation -5x²-12x+5-23+3x²=0, rearrange the equation to get the coefficients and then use the quadratic formula to solve for x.

Step-by-step explanation:

This is a quadratic equation of the form ax² + bx + c = 0. We can rearrange it to get the coefficients:




  • a = -5 + 3 = -2

  • b = -12

  • c = 5 - 23 = -18


Now we can use the quadratic formula to solve for x:


x = (-b ± √(b² - 4ac)) / (2a)


Plugging in the values, we get:
x = (-(-12) ± √((-12)² - 4(-2)(-18))) / (2(-2))

User Tal Aloni
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