Question

For the baseball team fundraiser, Ethan sold large boxes of candy for $3 each ar boxes of candy for $2 each. If he sold 37 boxes in all for a total of $96, how m large boxes than small boxes did he sell?

Answer 1

To solve this problem, we can use a system of equations to find the number of large boxes and small boxes sold. Ethan sold 22 large boxes and 15 small boxes, which means he sold 7 more large boxes than small boxes.

Step-by-step explanation:

To solve this problem, we can use a system of equations and solve for the number of large boxes and small boxes sold. Let x represent the number of large boxes sold, and y represent the number of small boxes sold.

We have two equations:

x + y = 37 (equation 1)

3x + 2y = 96 (equation 2)

We can solve this system of equations by substitution or elimination. Let's use elimination:

Multiply equation 1 by 2 so that the coefficients of y in both equations are the same:

2x + 2y = 74 (equation 3)

Now, subtract equation 3 from equation 2:

(3x + 2y) - (2x + 2y) = 96 - 74

x = 22

Substitute the value of x back into equation 1 to find y:

22 + y = 37

y = 37 - 22

y = 15

So, Ethan sold 22 large boxes and 15 small boxes.

Ethan sold 7 more large boxes than small boxes.