132k views
3 votes
The card game "Kings and Threes" has several rounds and uses

a standard 52-card deck. During the 6th round, a player is dealt 6
cards, which makes up their hand. How many different hands are
possible with no restrictions?

User Moe Matar
by
7.9k points

1 Answer

5 votes

Final answer:

The total number of different hands possible when a player is dealt 6 cards from a standard 52-card deck in the game "Kings and Threes" can be calculated using combinations, resulting in 20,358,520 different hands.

Step-by-step explanation:

The question asks about the number of different hands possible in the card game "Kings and Threes" when a player is dealt 6 cards from a standard 52-card deck. To find this, we use the concept of combinations in probability. The total number of different hands can be calculated as a combination of 52 cards taken 6 at a time, which is denoted as 52C6.

Using the formula for combinations, which is nCk = n! / (k!(n-k)!), where n is the total number of items, and k is the number of items to be chosen, we can calculate 52C6 as:

52C6 = 52! / (6!(52-6)!) = 52! / (6!46!) = (52 x 51 x 50 x 49 x 48 x 47) / (6 x 5 x 4 x 3 x 2 x 1)

After cancelling out the common factors, we find that the total number of different hands possible is 20,358,520.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories