Question

Mrs. Erastus, a pre-school teacher has 120 crayons, 30 pieces of paper and 60 bottles of glue to share among her learners for an art project with none left over. What is the largest possible number of groups that the learners can be divided into such that each group has the same number of crayons, paper and glue?

Answer 1

The greatest common divisor (GCD) of 120 crayons, 30 pieces of paper, and 60 bottles of glue is 30, rendering 30 as the largest possible number of equal groups for Mrs. Erastus's students for their art project.

Step-by-step explanation:

To find the largest possible number of groups that Mrs. Erastus's pre-school students can be divided into with an equal number of crayons, pieces of paper, and bottles of glue, we must determine the greatest common divisor (GCD) of the quantities 120, 30, and 60. The GCD is the largest number that can divide each of the quantities without leaving a remainder.

First, let us find the GCD of 120 and 30, which is 30. Then we use the GCD of 120 and 30 to find the GCD with 60. The GCD of 30 and 60 is also 30.

Therefore, the largest number of groups Mrs. Erastus can divide her students into, such that each group has the same number of crayons, pieces of paper, and bottles of glue, is 30.