Final answer:
The fundamental period of sin3x is approximately 2.094.
Step-by-step explanation:
To find the fundamental period of sin(3x), you need to understand how the period of the sine function is affected by coefficients inside the function. The fundamental period of the basic sine function, sin(x), is 2π radians. When you have sin(nx), where n is a coefficient, the new period becomes 2π/n. In the case of sin(3x), the fundamental period is 2π/3 radians. The fundamental period of the function sin3x can be found by using the formula:
T = (2π)/(3)
where T is the fundamental period and 3 is the coefficient of the x term. In this case, the fundamental period is approximately 2.094.