Question

Find the parametric equations for the line through the point P(2,1,−4) that is parallel to the plane x+2y−3z=5 and perpendicular to the line x=1+s,y=−3−s,z=5+2s,s∈R

Answer 1

The value of a in the equation (2a+25)° = (3a-15)° is 10.

Step-by-step explanation:

To find the value of a in the equation (2a+25)° = (3a-15)°, we can start by setting the two expressions equal to each other:

(2a+25)° = (3a-15)°

Next, we can solve for a by simplifying the equation:

2a+25 = 3a-15

10 = a

Therefore, the value of a is 10.