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Ants! Draw a picture and write an equation for each part of the task. Part 1. Nathan's mom has ants in her house. Ants have 6 legs. How man ants could there have been if she saw between 35 and 50 legs

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Final answer:

To solve this problem, we can use the fact that ants have 6 legs. The number of ants could be between approximately 5.8 and 8.3. Since we can't have a fraction of an ant, the possible number of ants is either 6 or 7.

Step-by-step explanation:

Ants! Drawing and Equations

To solve this problem, we can use the fact that ants have 6 legs. Let's assume the number of ants is 'x'. Since each ant has 6 legs, the total number of legs would be 6x. The question tells us that the number of legs observed by Nathan's mom is between 35 and 50. So, we can write the inequality 35 ≤ 6x ≤ 50.

Now, let's solve this inequality:

  1. Divide all the terms by 6: 35/6 ≤ x ≤ 50/6
  2. Simplify: 5.8 ≤ x ≤ 8.3

So, the number of ants could be between approximately 5.8 and 8.3. Since we can't have a fraction of an ant, the possible number of ants is either 6 or 7.

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