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Writing an equation in slope-intercept form given the slop A line passes through the point (-9,2) and has a slope of (4)/(3) Write an equation in slope-intercept form for this line.

User Immanuel
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Final answer:

To write the equation of the line in slope-intercept form, we can use the point-slope form and substitute the given slope and point into it.

Step-by-step explanation:

To write the equation of a line in slope-intercept form (y = mx + b), we need to know the slope (m) and the y-coordinate of a point on the line. In this case, the slope is 4/3, and the line passes through the point (-9, 2). So, we can plug in these values into the equation.

Using the point-slope form of a line, we have:
y - y1 = m(x - x1)
y - 2 = (4/3)(x - (-9))
y - 2 = (4/3)(x + 9)
y - 2 = (4/3)x + 12
y = (4/3)x + 14

Therefore, the equation of the line in slope-intercept form is y = (4/3)x + 14.

User CDspace
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