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The ga(s)/(o)il ratio for a certain chainsaw is 50 to 1 . a. How much oil (in gallons ) should be mixed with 12 gallons of gasoline? b. If 1 gallon equals 128 fluid ounces, write the answer to part a in fluid ounces. a. Mix gallons of oil with 12 gallons of gas. (Simplify your answer. )

User VeeeneX
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1 Answer

1 vote

Final answer:

For a 50 to 1 gas-to-oil ratio, mix 0.24 gallons or approximately 30.72 fluid ounces of oil with 12 gallons of gas.

Step-by-step explanation:

To mix the correct amount of oil with 12 gallons of gas for a chainsaw with a 50 to 1 gas-to-oil ratio, you need to divide 12 gallons by 50, since for every 50 parts of gas there is 1 part of oil:

  • 12 gallons / 50 = 0.24 gallons of oil.

To convert gallons to fluid ounces, you use the equivalence that 1 gallon equals 128 fluid ounces. Therefore:

  • 0.24 gallons × 128 fluid ounces/gallon = 30.72 fluid ounces.

You should mix 0.24 gallons or approximately 30.72 fluid ounces of oil with 12 gallons of gas.

User Daniel Ahrnsbrak
by
8.3k points
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